1 solutions

  • 0
    @ 2025-11-5 15:56:08

    C++ :

    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	int a[n+1];
    	a[1]=2;
    	for(int i=2;i<=n;++i)
    	a[i]=a[i-1]+i;
    	printf("%d",a[n]);
    	return 0;
    }
    

    Pascal :

    program hjc;
    var
     f:array[1..1000] of integer;
     n,i:integer;
    
    begin
     f[1]:=2;
     readln(n);
     for i:=2 to n do
      begin
       f[i]:=f[i-1]+i;
      end;
      writeln(f[n]);
    end.
    
    
    • 1

    Information

    ID
    17346
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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