1 solutions

  • 0
    @ 2025-11-5 15:55:30

    C :

    #include<stdio.h>
    main()
    {
    	int a,b;
    	for(a = 1;a<98;a++)
    	{
    		for(b = 1;b<98;b++)
    		{
    			if(a*2+b*4 == 386 && a+b == 98)
    				printf("%d,%d",a,b);
    		}
    	}
    	return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {int c,r;
     for(c=0;c<=98;c++)
     {	r=98-c;
        if(386==c*2+r*4)
      cout<<c<<","<<r<<endl;
     }return 0;
    }
    
    • 1

    【验证型】第6章:循环控制结构 6.15 鸡兔同笼

    Information

    ID
    17334
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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