1 solutions
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0
C :
#include<stdio.h> main() { int x,y,z; int n; int flag = 0; scanf("%d",&n); for(x = 1;x<n;x++) { for(y = 1;y<n;y++) { for(z = 1;z<n;z++) { if(x+y+z == n && 10*x+5*y+z == 100) { printf("%d,%d,%d\n",x,y,z); flag++; } } } } if(!flag) printf("不能兑换"); return 0; }
- 1
Information
- ID
- 17333
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By