1 solutions

  • 0
    @ 2025-11-5 15:54:56

    C :

    #include<stdio.h>
    main()
    {
    	float a=1,b=1,c,x,sum=0,i;
    	int n;
    	scanf("%d",&n);
    	for(i=1;i<=n;i++)
    	{
    		c=a+b;
    		x=c/b;
    		sum+=x;
    		a=b;
    		b=c;
    	}
    	printf("%0.2f",sum);
    	return 0;
    }
    

    C++ :

    #include <iostream> 
    #include <cstdio>
    using namespace std;
    int main()
    {
    	int n,p,q,t;
    	double ans;
    	p=1;
    	q=2;
    	ans=(double)q/p;
    	cin>>n;
    	for(int i=2;i<=n;i++)
    	{
    		t=p+q;
    		p=q;
    		q=t;
    		ans=ans+(double)q/p;
    	}
    	printf("%.2lf\n",ans);
    	return 0;
    }
    
    • 1

    【基础题】第6章:循环控制结构迭代 分数求和

    Information

    ID
    17322
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By