1 solutions
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0
C :
#include<stdio.h> main() { float a=1,b=1,c,x,sum=0,i; int n; scanf("%d",&n); for(i=1;i<=n;i++) { c=a+b; x=c/b; sum+=x; a=b; b=c; } printf("%0.2f",sum); return 0; }C++ :
#include <iostream> #include <cstdio> using namespace std; int main() { int n,p,q,t; double ans; p=1; q=2; ans=(double)q/p; cin>>n; for(int i=2;i<=n;i++) { t=p+q; p=q; q=t; ans=ans+(double)q/p; } printf("%.2lf\n",ans); return 0; }
- 1
Information
- ID
- 17322
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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