1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { int n,i,j,l[10]; char x[10][51]; scanf("%d",&n); getchar(); for(i=0;i<n;i++) { gets(x[i]); l[i]=strlen(x[i]); } for(i=0;i<n;i++) { for(j=0;j<l[i];j++) { if(x[i][j]=='a'||x[i][j]=='e'||x[i][j]=='i'||x[i][j]=='o'||x[i][j]=='u') x[i][j]=x[i][j]-32; else if(x[i][j]!='A'&&x[i][j]!='E'&&x[i][j]!='I'&&x[i][j]!='O'&&x[i][j]!='U'&&x[i][j]>='A'&&x[i][j]<='Z') x[i][j]=x[i][j]+32; } x[i][j]='\0'; } for(i=0;i<n;i++) { printf("%s",x[i]); if(i!=n-1) printf("\n"); } }C++ :
#include<stdio.h> #include<string.h> #define N 50 int main() { int i,j,T,counter=0; char a; char string[N]; scanf("%d",&T); getchar(); for(i=1;i<=T;i++) { gets(string); for(j=0;string[j]!='\0';j++) { if(string[j]>='A'&&string[j]<='Z') string[j]+=32; if(string[j]=='a'||string[j]=='e'||string[j]=='i'||string[j]=='o'||string[j]=='u') string[j]-=32; } printf("%s\n",string); } }
- 1
Information
- ID
- 17278
- Time
- 1000ms
- Memory
- 2MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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