1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { char x[10][201],y[10]; int n,i,j,l[10]; float k[10]; scanf("%d",&n); for(i=0;i<n;i++) { getchar(); scanf("%c %s",&y[i],x[i]); l[i]=strlen(x[i]); } for(i=0;i<n;i++) { k[i]=0.0; for(j=0;j<l[i];j++) { if(y[i]==x[i][j]||y[i]==x[i][j]+32||y[i]==x[i][j]-32) k[i]+=1; } } for(i=0;i<n;i++) { printf("%.5f",k[i]/l[i]); if(i!=n-1) printf("\n"); } }
- 1
Information
- ID
- 17269
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By