1 solutions

  • 0
    @ 2025-11-5 15:52:02

    C :

    #include<stdio.h>
    #include<string.h>
    int main()
    {
    	char x[10][201],y[10];
    	int n,i,j,l[10];
    	float k[10];
    	scanf("%d",&n);
    	for(i=0;i<n;i++)
    	{
    		getchar();
    		scanf("%c %s",&y[i],x[i]);
    		l[i]=strlen(x[i]);
    	}
    	for(i=0;i<n;i++)
    	{
    		k[i]=0.0;
    		for(j=0;j<l[i];j++)
    		{
    			if(y[i]==x[i][j]||y[i]==x[i][j]+32||y[i]==x[i][j]-32)
    				k[i]+=1;
    		}
    	}
    	for(i=0;i<n;i++)
    	{
    		printf("%.5f",k[i]/l[i]);
    		if(i!=n-1)
    		printf("\n");
    	}
    }
    
    • 1

    【设计型】第10章: 字符串 10.24 字母概率

    Information

    ID
    17269
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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