1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { char x[10][120],y[10][11],l[10]; int n,i,j,k,m; scanf("%d",&n); getchar(); for(i=0;i<n;i++) { gets(x[i]); l[i]=strlen(x[i]); } for(i=0;i<n;i++) { y[i][0]=x[i][0]-32; for(j=1,m=1;j<l[i];j++) { if(x[i][j]==' ') { j++; y[i][m]=x[i][j]-32; m++; } } y[i][m]='\0'; } for(i=0;i<n;i++) { printf("%s",y[i]); if(i!=n-1) printf("\n"); } return 0; }
- 1
Information
- ID
- 17266
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By