1 solutions
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0
C :
#include<stdio.h> #define N 100 int Even(int a) { if (a%2 == 0) return 1; else return 0; } int main() { int a[N]; int i = -1,sum = 0,j; do { i++; scanf("%d",&a[i]); }while(a[i]>0); for (j = 0; j<=i-1 ;j++) { if(!Even(a[j])) sum +=a[j]; } printf("%d",sum); return 0; }C++ :
#include<iostream> using namespace std; int even(int n); int main() { int x,jsh=0; cin>>x; while(x>0) { if(even(x)==0) jsh+=x; cin>>x; } cout<<jsh; return 0; } int even(int n) { if(n%2==0) return 1; else return 0; }
- 1
Information
- ID
- 17251
- Time
- 1000ms
- Memory
- 2MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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