1 solutions

  • 0
    @ 2025-11-5 15:51:09

    C :

    #include<stdio.h>
    main()
    {
    	unsigned long i,n,term = 1,sum = 0;
    	scanf("%lu",&n);
    	for(i = 1;;i++)
    	{
    		term = term*i;
    		sum = sum + term;
    		if(sum>=n)
    			break;
    	}
    	printf("%lu",i-1);
    }
    
    • 1

    【验证型】第六章:循环控制结构 6.11 不等式的解

    Information

    ID
    17250
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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