1 solutions
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0
C++ :
#include <iostream> using namespace std; int main() { int a[50][50],i,j,k,n,m; cin>>n; m=2*n-1; for(k=0;k<n;k++) { for(i=k;i<m-k;i++) { a[i][k]=k+1; a[i][m-1-k]=k+1; } for(j=k;j<m-k;j++) { a[k][j]=k+1; a[m-1-k][j]=k+1; } } for(i=0;i<m;i++) { for(j=0;j<m;j++) cout<<a[i][j]<<" "; cout<<endl; } return 0; }
- 1
Information
- ID
- 17240
- Time
- 1000ms
- Memory
- 2MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By