1 solutions

  • 0
    @ 2025-11-5 15:50:38

    C :

    #include<stdio.h>
    int main()
    {
    	int n,m,i,j,flag;
    	flag=0;
    	scanf("%d",&n);
    	int a[n];
    	for(i=0;i<n;i++)
    	scanf("%d",&a[i]);
    	scanf("%d",&m);
    	for(i=0;i<n;i++)
    	{
    		if(m==a[i])
    		{
    		for(j=i;j<n-1;j++)
    		a[j]=a[j+1];
    		flag++;
        	}
        }
        if(flag==0)
        printf("不存在这个数!");
        else
        for(i=0;i<n-1;i++)
        {
        	printf("%d ",a[i]);
        }
    }
    

    C++ :

    #include <iostream> 
    using namespace std;
    int main() 
    {  
        int a[50],n,x,i,j;  
        cin>>n;   
        for(i=0;i<n;i++)    
            cin>>a[i];   
        cin>>x;  
        for(i=0;i<n;i++)  
        {   
            if(a[i]==x)      
            break;
        }   
        if(i==n)   
        cout<<"不存在这个数"<<endl;  
        else   
        {
    	    for(j=i;j<n-1;j++)      
                a[j]=a[j+1];   
            n--;   
            for(i=0;i<n;i++)    
                cout<<a[i]<<" ";
        }
        return 0;  
    }
    
    • 1

    Information

    ID
    17239
    Time
    1000ms
    Memory
    2MiB
    Difficulty
    (None)
    Tags
    # Submissions
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