1 solutions

  • 0
    @ 2025-11-5 15:50:21

    C :

    #include<stdio.h>
    #include<string.h>
    int main()
    {
    	char x[2002],a[2][1001],b[1001];
    	int i,j,k,l,m;
    	gets(x);
    	l=strlen(x);
    	for(i=0;i<2;i++)
    	{
    		for(j=0,k=0,m=0;j<l;j++)
    		{
    			if(x[j]!='&')
    			{
    				a[m][k]=x[j];
    				k++;
    			}
    			else
    			{
    				a[m][k]='\0';
    				m++;
    				k=0;
    			}
    		}
    	}
    	l=strlen(a[1]);
    	for(i=0,m=0;i<l;i++)
    	{
    		b[m]=a[1][l-m-1];
    		m++;
    	}
    	b[m]='\0';
    	if(strcmp(a[0],b)==0)
    	printf("YES");
    	else	printf("NO");
    }
    
    • 1

    Information

    ID
    17233
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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