1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { char x[2002],a[2][1001],b[1001]; int i,j,k,l,m; gets(x); l=strlen(x); for(i=0;i<2;i++) { for(j=0,k=0,m=0;j<l;j++) { if(x[j]!='&') { a[m][k]=x[j]; k++; } else { a[m][k]='\0'; m++; k=0; } } } l=strlen(a[1]); for(i=0,m=0;i<l;i++) { b[m]=a[1][l-m-1]; m++; } b[m]='\0'; if(strcmp(a[0],b)==0) printf("YES"); else printf("NO"); }
- 1
Information
- ID
- 17233
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By