1 solutions

  • 0
    @ 2025-11-5 15:47:06

    C :

    #include<stdio.h>
    #define N 5
    main()
    {
    	int a[N];
    	int i;
    	for(i = 0;i < N;i++)
    	{
    		scanf("%d",&a[i]);
    	}
    	for(i = 0;i < N;i++)
    	{
    		if(a[i]%2 == 1)
    			printf("奇数\n");
    		else 
    			printf("偶数\n");
    	}
    	return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    
    int main()
      
    {
    int a[5];
      int i;
      for(i = 0; i <5;i++)
        cin>>a[i];
      for(i = 0; i < 5;i++)
        if(a[i]%2)cout<<"奇数"<<endl;
        else cout << "偶数" << endl;
        return 0;
    }
    
    • 1

    【验证型】第5章:选择控制结构 5.2 奇偶性

    Information

    ID
    17166
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
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