1 solutions
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0
C :
#include<stdio.h> #define N 5 main() { int a[N]; int i; for(i = 0;i < N;i++) { scanf("%d",&a[i]); } for(i = 0;i < N;i++) { if(a[i]%2 == 1) printf("奇数\n"); else printf("偶数\n"); } return 0; }C++ :
#include<iostream> using namespace std; int main() { int a[5]; int i; for(i = 0; i <5;i++) cin>>a[i]; for(i = 0; i < 5;i++) if(a[i]%2)cout<<"奇数"<<endl; else cout << "偶数" << endl; return 0; }
- 1
Information
- ID
- 17166
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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