1 solutions
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0
C :
#include<stdio.h> #define N 5 main() { int a[N]; int i,b; for(i = 0;i<N;i++) scanf("%d",&a[i]); for(i = 0;i < N;i++) { if(a[i]>=0) printf("%d\n",a[i]); else { b = -a[i]; printf("%d\n",b); } } return 0; }C++ :
#include<iostream> using namespace std; int main() { int i; int nNum[5] = {0}; for(i = 0; i < 5; i++) { cin >> nNum[i]; } for(i = 0; i < 5; i++) { if(nNum[i] < 0) { cout << -nNum[i] << endl; continue; } cout << nNum[i] << endl; } return 0; }
- 1
Information
- ID
- 17100
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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