1 solutions
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0
C :
#include <stdio.h> #include<math.h> int main() { int m,n,i,j,k; while(scanf("%d",&n)!=EOF) { m=0; k=3; if(n<=2) printf("N\n"); else { for(i=0;i<n;i++) { m+=k; k++; } if((m-2*n)%2==0) printf("Y\n"); else printf("N\n"); } } }C++ :
#include<cstdio> #include<cstring> #include<cmath> #include<iostream> #include<algorithm> using namespace std; int main() { int n; while(scanf("%d",&n)!=EOF) { if(n==0) return 0; if(n%4==0||(3*n-1)%4==0) printf("Y\n"); else printf("N\n"); } return 0; }
- 1
Information
- ID
- 16828
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By