1 solutions

  • 0
    @ 2025-11-5 15:27:46

    C :

    #include<stdio.h>
    int main(){
    int i;
    for(i=100;i<=200;i++)
      if(i%3!=0)
        printf("%d ",i);
    printf("\n");
    return 0;
    }
    

    C++ :

    #include <stdio.h>
    int main() {
    	int i;
    	for (i = 100;i <= 200;i++)
    		if (i % 3 != 0)
    			printf("%d ", i);
    	printf("\n");
    	return 0;
    }
    
    

    Pascal :

    var
      a:longint;
    begin
      for a:=100 to 200 do
      begin
      if a mod 3<>0 then write(a,' ');
      end;
    end.
    

    Java :

    public class Main {
    	public static void main(String args[]) {
    		for(int i=100;i<=200;i++){
    			if(i%3!=0)
    				System.out.printf("%d ",i);
    		}
    	}
    }
    

    Python :

    print ' '.join(str(x) for x in xrange(100, 201) if x%3),''
    
    • 1

    Information

    ID
    16819
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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