1 solutions

  • 0
    @ 2025-11-5 15:25:47

    C++ :

    #include<iostream>
    #include<algorithm>
    #include<cstdio>
    #include<queue>
    using namespace std;
    const int N=1e6+10;
    const int mod=1e9+7;
    long long a[N],sum[2*N];
    int main()
    {
        int n,count;
        while(cin>>n && n)
        {
            deque< int >aa;
            count=0;sum[0]=0;
            for(int i=1;i<=n;i++)
            {
                scanf("%lld",&a[i]);
                sum[i]=sum[i-1]+a[i];
            }
            for(int i=n+1,j=1;j<n;i++,j++)
                sum[i]=sum[i-1]+a[j];
                for(int i=1;i<=n;i++)
                {
                    aa.push_back(sum[i]);
                    if(sum[i]<0)
                        count=1;
                }
                aa.pop_front();
            for(int i=n+1,j=1; i<2*n; i++, j++)
            {
                  aa.push_back(sum[i]);
                  if(aa.front()-sum[j]<0)
                    count++;
                  aa.pop_front();
            }
          cout<<n-count<<endl;
        }
        return 0;
    }
    
    
    • 1

    Information

    ID
    16778
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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