1 solutions
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0
C++ :
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int a[3],i,j,tmp; scanf("%d%d%d",&a[0],&a[1],&a[2]); for(i=0;i<2;i++) for(j=2;j>i;j--) { if(a[j]<a[j-1]) { tmp=a[j]; a[j]=a[j-1]; a[j-1]=tmp; } } printf("%d %d %d ",a[0],a[1],a[2]); return 0; }
- 1
Information
- ID
- 16727
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By