1 solutions

  • 0
    @ 2025-11-5 15:23:07

    C++ :

    #include <stdio.h>
    #include <stdlib.h>
    
    int main(int argc, char *argv[])
    {
        int a[3],i,j,tmp;
        scanf("%d%d%d",&a[0],&a[1],&a[2]);
        for(i=0;i<2;i++)
        for(j=2;j>i;j--)
        {
            if(a[j]<a[j-1])
            {
            tmp=a[j];
            a[j]=a[j-1];
            a[j-1]=tmp;
            }
        }
        printf("%d %d %d ",a[0],a[1],a[2]);
        
    
      return 0;
    }
    
    
    • 1

    C语言程序设计教程(第三版)课后习题10.1

    Information

    ID
    16727
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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