1 solutions
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0
C :
#include <stdio.h> int main() { for (int i = 10; i <= 1000; i ++) { if (!(i % 2) && !(i % 3) && !(i % 7)) { printf("%d\n", i); } } return 0; }C++ :
#include <stdio.h> int a[100000]; int main() { for(int i=10;i<=1000;i++) { if(i%2==0&&i%3==0&&i%7==0) printf("%d\n",i); } return 0; }Pascal :
var i:longint; begin for i:=10 to 1000 do if i mod 2=0 then if i mod 3=0 then if i mod 7=0 then writeln(i); end.
- 1
Information
- ID
- 16706
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By