1 solutions
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0
C :
#include <stdio.h> int sum(int n) { int s = 0; do { s += n; } while (n --); return s; } int main() { int n; scanf("%d", &n); printf("%d\n", 2 * n + sum(n - 1) * 3); return 0; }C++ :
#include <stdio.h> int a[100000]; int main() { int n; while(scanf("%d",&n)!=EOF) { long long sum=2; for(int i=1;i<n;i++) sum+=i*3+2; printf("%lld\n",sum); } return 0; }
- 1
Information
- ID
- 16705
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
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