1 solutions

  • 0
    @ 2025-11-5 15:22:02

    C :

    #include <stdio.h>
    
    int sum(int n) {
        int s = 0;
        do {
            s += n;
        } while (n --);
        return s;
    }
    
    int main() {
        int n;
        scanf("%d", &n);
        printf("%d\n", 2 * n + sum(n - 1) * 3);
        return 0;
    }
    

    C++ :

    #include <stdio.h>
    int a[100000];
    int main()
    {
    	int n;
    	while(scanf("%d",&n)!=EOF)
    	{
    		long long sum=2;
    		for(int i=1;i<n;i++)
    		sum+=i*3+2;
    		printf("%lld\n",sum);
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    16705
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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