1 solutions
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0
C :
#include <stdio.h> int main() { float fahrenheit; scanf("%f", &fahrenheit); printf("%.2f\n", 5 / 9.0 * (fahrenheit - 32.0)); return 0; }C++ :
#include <stdio.h> int a[100000]; int main() { double n; while(scanf("%lf",&n)!=EOF) { printf("%.2lf\n",(n-32)*5/9); } return 0; }Java :
import java.text.DecimalFormat; import java.util.Scanner; public class Main { public static void main(String[] args) { DecimalFormat df=new DecimalFormat(".00"); Scanner cin = new Scanner(System.in); double a; while (cin.hasNext()) { a = cin.nextDouble(); a=(a-32)*5/9; System.out.println(df.format(a)); } } }
- 1
Information
- ID
- 16701
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By