1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int a[10000],b[10000],c[10000]; string add(string s1,string s2) { int len1=s1.size(); int len2=s2.size(); int len3=max(len1,len2); for(int i=len1-1,j=0;i>=0;i--,j++) a[j]=s1[i]-'0'; for(int i=len2-1,j=0;i>=0;i--,j++) b[j]=s2[i]-'0'; int jw=0; for(int i=0;i<len3;i++) { c[i]=a[i]+b[i]+jw; jw=c[i]/10; c[i]=c[i]%10; } if(jw)c[len3++]=1; string s3; for(int i=len3-1;i>=0;i--) s3+=c[i]+'0'; return s3; } int main(){ string s1,s2; cin>>s1>>s2; cout<<add(s1,s2); return 0; }Pascal :
var s1,s2:string; x1,x2,x:array[0..1000]of longint; i,j,l,l1,l2:longint; begin readln(s1); readln(s2); l1:=length(s1); l2:=length(s2); for i:=1 to l1 do x1[i]:=ord(s1[l1+1-i])-48; for i:=1 to l2 do x2[i]:=ord(s2[l2+1-i])-48; if l1>l2 then l:=l1 else l:=l2; j:=0; for i:=1 to l do begin x[i]:=(x1[i]+x2[i]+j)mod 10; j:=(x1[i]+x2[i]+j) div 10; end; if j>0 then begin inc(l);x[l]:=j;end; for i:=l downto 1 do write(x[i]); end.
- 1
Information
- ID
- 16684
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By