1 solutions
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0
C :
#include<stdio.h> int main() { long n[3]; int i, j, k; long t; long max, min; for (i = 0; i < 3; i++) { scanf("%ld", &n[i]); } max = min = n[0]; for (j = 0; j < 3; j++) { if (n[j] > max) max = n[j]; } for (k = 0; k < 3; k++) { if (n[k] < min) min = n[k]; } printf("%ld %ld\n", max, min); return 0; }Pascal :
var i,j,k,m,n:longint; begin read(i,j,k); if (i>j) and (i>k) then write(i,' ') else if j>k then write(j,' ') else write(k,' '); if (i<j) and (i<k) then write(i) else if j<k then write(j) else write(k); end.
- 1
Information
- ID
- 16628
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By