1 solutions
-
0
C :
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int a[3][3]; int sum1,sum2,q,w; for(q=0;q<3;q++) for(w=0;w<3;w++) { scanf("%d",&a[q][w]); } sum1=a[0][0]+a[1][1]+a[2][2]; sum2=a[0][2]+a[1][1]+a[2][0]; printf("%d %d",sum1,sum2); return 0; }C++ :
#include<iostream> using namespace std; int a[4][4]; int main() { for (int i=1; i<=3; i++) for (int j=1; j<=3; j++) cin>>a[i][j]; int sum1=0,sum2=0; for (int i=1; i<=3; i++) { sum1+=a[i][i]; sum2+=a[i][4-i]; } cout<<sum1<<" "<<sum2<<endl; return 0; }
- 1
Information
- ID
- 16607
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By