1 solutions

  • 0
    @ 2025-11-5 15:17:08

    C :

    #include <stdio.h>
    #include <stdlib.h>
    
    int main(int argc, char *argv[])
    {
      int a[3][3];
      int sum1,sum2,q,w;
      for(q=0;q<3;q++)
      for(w=0;w<3;w++)
      {
        scanf("%d",&a[q][w]);
      }
      sum1=a[0][0]+a[1][1]+a[2][2];
      sum2=a[0][2]+a[1][1]+a[2][0];
      printf("%d %d",sum1,sum2);
    
      return 0;
    }
    
    

    C++ :

    #include<iostream>
    using namespace std;
    int a[4][4];
    int main()
    {
    	for (int i=1; i<=3; i++)
    		for (int j=1; j<=3; j++) cin>>a[i][j];
    	int sum1=0,sum2=0;
    	for (int i=1; i<=3; i++)
    	{
    		sum1+=a[i][i];
    		sum2+=a[i][4-i];
    	}
    	cout<<sum1<<" "<<sum2<<endl;
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题7.3

    Information

    ID
    16607
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By