1 solutions

  • 0
    @ 2025-11-5 15:15:35

    C :

    #include <stdio.h>
    #include <stdlib.h>
    
    int main(int argc, char *argv[])
    {
      double a=2,b=1;
      int m,i;
      double sum=2;
      scanf("%d",&m);
      for(i=2;i<=m;i++)
      {
            int k;
            k=b;
            b=a;
            a+=k;
            sum+=a/b;
      }
      printf("%.2lf",sum);
    
      return 0;
    }
    
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	double fz=2,fm=1,sum=0;
    	for (int i=1; i<=n; i++)
    	{
    		sum+=fz/fm;
    		double t=fz;
    		fz+=fm;
    		fm=t;
    	}
    	printf("%.2lf\n",sum);
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.8

    Information

    ID
    16579
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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