1 solutions
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0
C :
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { double a=2,b=1; int m,i; double sum=2; scanf("%d",&m); for(i=2;i<=m;i++) { int k; k=b; b=a; a+=k; sum+=a/b; } printf("%.2lf",sum); return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { int n; cin>>n; double fz=2,fm=1,sum=0; for (int i=1; i<=n; i++) { sum+=fz/fm; double t=fz; fz+=fm; fm=t; } printf("%.2lf\n",sum); return 0; }
- 1
Information
- ID
- 16579
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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