1 solutions

  • 0
    @ 2025-11-5 15:15:03

    C :

        #include <stdio.h>
        #include <stdlib.h>
        #include<math.h>
        int main(int argc, char *argv[])
        {
        int n,i,k,sum=0;
        scanf("%d",&n);
        for(i=1;i<=n;i++)
        for(k=0;k<i;k++)
        {
         sum+=2*pow(10,k);
        }
    
        printf("%d\n",sum);
    
        return 0;
        }
    
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int a=2,n;
    	long t=0,sum=0;
    	cin>>n;
    	for (int i=1; i<=n; i++)
    	{
    		t=10*t+a;
    		sum+=t;
    	}
    	cout<<sum<<endl;
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.3

    Information

    ID
    16569
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
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