1 solutions

  • 0
    @ 2025-11-5 15:13:17

    C :

    #include<stdio.h>
    int main()
    {
    	int x,y;
    	while(scanf("%d",&x)!=EOF)
    	{
    		if(x<1)
    			y=x;
    		else if(x>=1&&x<10)
    			y=2*x-1;
    		else
    			y=3*x-11;
    		printf("%d\n",y);
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    int tab(int x)
    {
    	int y;
    	if(x<1)
    		y=x;
    	else if(x<=1||x<10)
    		     y=2*x-1;
        else
    		y=3*x-11;
    	return y;
    }
    int main()
    {
    	int x;
    	scanf("%d",&x);
    	printf("%d\n",tab(x));
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题5.5

    Information

    ID
    16533
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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