1 solutions

  • 0
    @ 2025-11-5 15:11:55

    C :

    #include <stdio.h>
    
    int main()
    {
        //freopen("a.in", "r", stdin);
        //freopen("A.out", "w", stdout);
        int n;
        while(scanf("%d", &n), n)
        {
            printf("%d\n", n / 2);
        }
        return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int n;
    	int sum,count;            //能兑换到的瓶数 
    	while(cin>>n&&n!=0)
    	{
    		sum=0;count=0;
    		if(n>=3)
    		{
    			while(n>2)
    			{
    				sum=n/3;
    				n=n-3*sum+sum;        //剩余的瓶数
    				count+=sum;
    			}
    			if(n==2)
    			{
    				count++;
    			}
    		cout<<count<<endl;
    		}
    		else
    		{
    			cout<<0<<endl;
    		} 
    	}	
    } 
    
    • 1

    Information

    ID
    16504
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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