1 solutions
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0
C :
#include <stdio.h> int main() { int year, leap; scanf("%d", &year); leap = 0; //0表示非闰年 if(year % 4 == 0){ if(year % 100 != 0) leap = 1; } if(year % 400 == 0) leap = 1; if(leap) printf("yes\n"); else printf("no\n"); return 0; }C++ :
#include<iostream> using namespace std; int main() { int a; cin>>a; if(a%4==0&&a%100!=0||a%400==0) cout<<"yes"<<endl; else cout<<"no"<<endl; }Pascal :
program Jerry001; var a:integer; begin readln(a); if (a mod 4=0) and (a mod 100<>0) then writeln('yes') else if a mod 400=0 then writeln('yes') else writeln('no'); end.
- 1
Information
- ID
- 16489
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
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- 0
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