1 solutions
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0
C :
#include <stdio.h> int main() { int a; float b1,b; while(scanf("%d",&a) != EOF) { if (a==1) { b1=0.7*0.7*0.7*0.7*0.7*0.7+6*0.7*0.7*0.7*0.7*0.7*0.3 +15*0.7*0.7*0.7*0.7*0.3*0.3; b=1-b1; } else b =0.0001; printf("%.4f\n",b); } return 0; }C++ :
#include <string> int main() { int a; while(scanf("%d",&a) != EOF) {if (a==1){ printf("%.4f\n",0.2557);} else { printf("%.4f\n",0.0001); } } }Pascal :
program y1; var a:integer; begin readln(a); if a<>0 then writeln('0.2557') else writeln('0.0001'); end.Java :
import java.util.Scanner; public class Main{ public static void main(String[] args) { Scanner reader = new Scanner(System.in); int a; while(reader.hasNext()){ a = reader.nextInt(); if(a==0){ System.out.println("0.0001"); } else if(a==1){ System.out.println("0.2557"); } } } }
- 1
Information
- ID
- 16448
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By