1 solutions

  • 0
    @ 2025-11-5 15:07:47

    C :

    #include <stdio.h>
     
    int main()
     
    {
        int a;
       float b;
        while(scanf("%d",&a) != EOF)
     {
     if (a==1) 
       b=0.5043;
     
        
      else if (a==0)
    		b=0.0001;
            printf("p=%.4f\n",b);
    		
    }
        return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main(){
    	int a;
    	cin>>a;
    	if(a==1)
    	   cout<<"p=0.5043\n";
    	else
       	   cout<<"p=0.0001\n";
    	return 0;
    }
    

    Java :

    import java.text.DecimalFormat;
    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args){
    		
    		float f[] = new float[2];
    		Scanner reader = new Scanner(System.in); 
    		int a;
    		DecimalFormat df=new DecimalFormat("#0.0000");
    		while(reader.hasNext()){
    			a = reader.nextInt();
    			if(a==1){
    				f = null;
    				f =new float[1];
    				f[0]=(float)0.5043;	
    			}
    			else {
    				f = null;
    				f =new float[1];
    				f[0] = (float) 0.0001;
    			}
    			for(int i=0;i<f.length;i++){
    				System.out.println("p="+df.format(f[i]));
    			}
    		}
    	}
    }
    
    • 1

    Information

    ID
    16430
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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