1 solutions
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0
C :
#include <stdio.h> int main() { int a; float b; while(scanf("%d",&a) != EOF) { if (a==1) b=28.0/45; else if(a==2) b=1.0/45; else if(a==3) b=16.0/45; else if(a==4) b=1.0/5; else if (a==0) b=0.0001; printf("%.4f\n",b); } return 0; }C++ :
#include <stdio.h> int main() { int a; float b; while(scanf("%d",&a) != EOF) {if (a==1) b=28.0/45; //将“作业答案”替换为该题答案。若有多行,用多行重复输出。 else if (a==2) b=1.0/45; else if(a==3) b=16.0/45; else if(a==4) b=1.0/5; else b=0.0001; printf("%.4f\n",b); } return 0; }Java :
import java.text.DecimalFormat; import java.util.Scanner; public class Main { public static void main(String[] args){ float f[] = new float[2]; Scanner reader = new Scanner(System.in); int a; DecimalFormat df=new DecimalFormat("#0.0000"); while(reader.hasNext()){ a = reader.nextInt(); switch(a){ case 1:f = null; f =new float[1]; f[0]=(float)28/45; break; case 2:f = null; f =new float[1]; f[0]=(float)1/45; break; case 3:f = null; f =new float[1]; f[0]=(float)16/45; break; case 4:f = null; f =new float[1]; f[0]=(float)1/5; break; default: f = null; f =new float[1]; f[0]=(float)0.0001; break; } for(int i=0;i<f.length;i++){ System.out.println(df.format(f[i])); } } } }
- 1
Information
- ID
- 16427
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By