1 solutions

  • 0
    @ 2025-11-5 15:05:30

    C :

    #include<stdio.h>
    int main()
    {
    	int n,k,i=1;
        scanf("%d",&n);
    	while(i <= n)
    	{
    		k = 1;
    	    while (k <= i)
    		{
    	       printf("%d",k);
    		   k = k + 1;
    		   if (k <= i)
    		   {
    		     printf(" ");
    		   }
    		}
    		printf("\n");
    		i = i + 1;
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    int main()
    {
    	int n,i,j,count;
    	scanf("%d",&n);
    	for(i = 1 ; i <= n ; i ++)
    	{
    		for(j = 1 ; j <= i;j ++)
    		{
    			count ++;
    			if ( j == 1)
    				printf("%d",1);
    			else if (j != 1)
    				printf(" %d",j);
    		}
    			
    		printf("\n");
    	}
    	return 0;
    }
    

    Pascal :

    program xzy1;
      var
        n,i,j:integer;
      begin
        readln(n);
        for i:=1 to n do
          begin
          for j:=1 to i-1 do
            write(j,' ');
            writeln(i);
          end;
      end.
    
    • 1

    Information

    ID
    16385
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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