1 solutions
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0
C :
#include<stdio.h> int main() { long long ji, n; while(scanf("%lld",&n)==1) { if(n<=2) { ji = n; } else if(n%2) { ji = n*(n-1)*(n-2); } else { if(n%3) { ji = n*(n-1)*(n-3); } else ji= (n-1)*(n-2)*(n-3); } printf("%lld\n",ji); } return 0; }C++ :
#include<iostream> using namespace std; int main() { long long n, ans; while(cin >> n) { if(n <= 2) { ans = n; } else if(n % 2) { ans = n * (n - 1) * (n - 2); } else { if(n%3) ans = n * (n-1) * (n-3); else ans=(n-1) * (n-2) * (n-3); } cout << ans << endl; } return 0; }
- 1
Information
- ID
- 16327
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By