1 solutions

  • 0
    @ 2025-11-5 14:59:21

    C :

    #include<stdio.h>
    int main()
    {
        int a[31][30]={0};
        int i,j;
        int n,m;
        scanf("%d %d",&n,&m);
        a[0][0]=1;
        for(i=1;i<=m;i++)
        {
            a[i][0]=a[i-1][1]+a[i-1][n-1];
            a[i][n-1]=a[i-1][0]+a[i-1][n-2];
            for(j=1;j<n-1;j++)
                a[i][j]=a[i-1][j-1]+a[i-1][j+1];
        }
        printf("%d\n",a[m][0]);
        return 0;
    }
    
    

    C++ :

    #include <iostream>
    #include <algorithm>
    using namespace std;
    int n,m;
    struct juzhen{
        int a[40][40];
    }x, ans;
    juzhen cul(juzhen p, juzhen q)
    {
        juzhen res;
        for (int i=1; i<=n; i++)
        for (int j=1; j<=n; j++)
        {
            res.a[i][j]=0;
            for (int k=1; k<=n; k++)
                res.a[i][j]+= p.a[i][k]*q.a[k][j];
        }
        return res;
    }
    void pow(int p)
    {
        for (int i=1; i<=n; i++)
            ans.a[i][i]=1;
        while (p)
        {
            if (p&1) ans = cul(ans, x);
            x = cul(x, x);
            p>>=1;
        }
    }
    int main()
    {
        cin>>n>>m;
        for (int i=1; i<=n; i++)
        {
            if (i==1){
                x.a[1][2]=1;
                x.a[1][n]=1;
            }
            else if (i==n){
                x.a[n][n-1]=1;
                x.a[n][1]=1;
            }
            else{
                x.a[i][i+1]=1;
                x.a[i][i-1]=1;
            }
        }
        pow(m);
        cout<<ans.a[1][1]<<endl;
        return 0;
    }
    
    
    • 1

    Information

    ID
    16302
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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