1 solutions

  • 0
    @ 2025-11-5 14:58:56

    C :

    #include <stdio.h>
    int data[11] ;
    int main() {
        int n , k ; scanf("%d%d" , &k , &n ) ;
        data[0] = 1 ;
        for( int i = 1 ; i < 11 ; i ++ ) {
            data[i] = data[i-1] * k ;
        }
        int res = 0 ;
        int p = 0 ;
        while(n) {
            if(n&1)res += data[p] ;
            n/=2 ; p ++ ;
        }
        printf("%d\n" , res ) ;
        return 0 ;
    }
    
    

    C++ :

    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<map>
    using namespace std;
    int main()
    {
        int m,n,k,t;
        int a[15];
        cin>>m>>n;
        k=0;
        while(n>=1)
        {
            a[k++]=n%2;
            n/=2;
        }
    int     sum=0;
        for(int i=0;i<=k;i++)
            if(a[i]==1)
              sum=pow(m,i)+sum;
              cout<<sum<<endl;
        return 0;
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	static int n;
    	static double m;
    	static int[] data;
    	static int count;
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		m=sc.nextDouble();
    		n=sc.nextInt();
    		data = new int[n];
    		Series(0);
    		System.out.println(data[n-1]);
    	}
    	public static void Series(int t) {
    		if(count==n) {
    			return;
    		}
    		if(t==0) {
    			data[count]=1;
    			count++;
    			Series(t+1);
    		}
    		else {
    			data[count]=(int) Math.pow(m, t);
    			count++;
    			int s=count;
    			for(int i=0;i<s-1;i++) {
    				if(count==n) {
    					return;
    				}
    				data[count]=(int) (data[i]+Math.pow(m, t));
    				count++;
    			}
    			Series(t+1);
    		}
    	}
    }
    
    
    • 1

    Information

    ID
    16294
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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