1 solutions
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0
C :
#include<stdio.h> int main() { int x,y,min=369,mx,my; for(x=0;x<=369/69;x++) { y=(369-x*69)%39; if(y<min) { min=y; mx=x; my=(369-x*69)/39; } } printf("%d %d %d\n",mx,my,min); return 0; }C++ :
#include<iostream> using namespace std; int main() { int a=369,b; for(int i=1;i<=7;++i) { if((369-39*i)%69<=a) {a=(369-39*i)%69;b=i;} } cout<<(369-39*b)/69<<" "<<b<<" "<<a<<endl; }
- 1
Information
- ID
- 16279
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By