1 solutions
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0
C++ :
#include<stdio.h> int leap(int y) { return y%4==0&&y%100!=0||y%400==0?1:0; } int main() { int t,y,m,d,i,s; scanf("%d",&t); while(t--) { scanf("%d-%d-%d",&y,&m,&d); s=6570; if(m==2&&d==29) { if(!leap(y+18)) printf("-1\n"); else { for(i=y+1;i<=y+18;i++) if(!leap(i)) s--; printf("%d\n",s); } } else { if(m<=2) { for(i=y;i<y+18;i++) if(leap(i)) s++; } else for(i=y+1;i<=y+18;i++) if(leap(i)) s++; printf("%d\n",s); } } return 0; }
- 1
Information
- ID
- 1326
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By