#include<stdio.h>
#define h 100
int a[h][h],b[h][h],sum[h][h];
int main()
{
	int n,m,i=0,j=0,ant=0;
	scanf( "%d%d" ,&n , &m);
	
	for(i=0;i<n;i++)
		for(j=0;j<m;j++)
		 scanf("%d",&a[i][j]);
	
	
	
	
	for(i=0;i<n;i++)
	  for(j=0;j<m;j++)
	   scanf("%d" ,&b[i][j]);

    for(i=0;i<n;i++)
		for(j=0;j<m;j++)
		 sum[i][j]=a[i][j]+b[i][j];

	for(i=0;i<n;i++)
		for(j=0;j<m;j++)
		{
			printf("%d ",sum[i][j]);
			ant++;
			if(ant%3==0) printf("\n");
		}
		

}

1 comments

  • @ 2023-12-10 23:59:26

    请自行判断,给你个提示: 输入:

    4 4
    1 1 1 1
    1 1 1 1
    1 1 1 1
    1 1 1 1
    1 1 1 1
    1 1 1 1
    1 1 1 1
    1 1 1 1
    

    输出:

    2 2 2 2
    2 2 2 2
    2 2 2 2
    2 2 2 2
    

    你的答案

    2 2 2 
    2 2 2 
    2 2 2 
    2 2 2 
    2 2 2 
    2 
    
    • 1

    Information

    ID
    289
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    6
    Tags
    # Submissions
    62
    Accepted
    21
    Uploaded By